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30 November, 07:19

How to find the square root of 5x-25=0

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  1. 30 November, 07:45
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    x = ± √5 = ± 2.2361

    Step-by-step explanation:

    Two solutions were found:

    x = ± √5 = ± 2.2361

    Step by step solution:

    Step 1:

    Equation at the end of step 1:

    5x2 - 25 = 0

    Step 2:

    Step 3:

    Pulling out like terms:

    3.1 Pull out like factors:

    5x2 - 25 = 5 • (x2 - 5)

    Trying to factor as a Difference of Squares:

    3.2 Factoring: x2 - 5

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 5 is not a square!

    Ruling : Binomial can not be factored as the difference of two perfect squares.

    Equation at the end of step 3:

    5 • (x2 - 5) = 0

    Step 4:

    Equations which are never true:

    4.1 Solve : 5 = 0

    This equation has no solution.

    A a non-zero constant never equals zero.

    Solving a Single Variable Equation:

    4.2 Solve : x2-5 = 0

    Add 5 to both sides of the equation:

    x2 = 5

    When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

    x = ± √ 5

    x = ± √5 = ± 2.2361
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