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19 July, 00:21

Set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three. Set Y is made up of the possible ways five students can be formed into groups of three if student A must be in all possible groups.

Which statements about the situation are true? Check all that apply.

Set X has 10 possible groupings.

X Y

Set Y = {ABC, ABD, ABE, ACD, ACE, ADE}

If person E must be in each group, then there can be only one group.

There are three ways to form a group if persons A and C must be in it.

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  1. 19 July, 00:36
    0
    1) it's a combination with n=5 & r=3 = = > 10 so set x=10

    2) it's a combination with n=4 & r=2 = = > 6 set y is true

    3) Sure, one group where E is always present

    4) Indeed since it's a combination with n=3 & r=2==>3
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