Ask Question
2 September, 21:45

Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1

+5
Answers (2)
  1. 2 September, 21:47
    0
    Center: (0, 0); Vertices: (0, - 25), (0, 25); Foci: (0, - 15), (0, 15)

    Step-by-step explanation:

    The center is (0,0) because there is no (h, k)

    The vertices are (0, - 25), (0, 25) because we use the formula (x-h) ^2/b^2 + (y-k) ^2/a^2 = 1, since the y's denominator is larger.

    The foci are (0, - 15), (0, 15) because we use the formula a^2=b^2+c^2 to find the foci, a=625 and b=400, simplify to c= + or - 15 and you get your foci.
  2. 2 September, 22:15
    0
    x^2/400 + x^2/625

    (x-0) ^2/400) + (y-0^2/625)

    x^2=400

    X=sqrt. 400

    x = 20

    y^2=625

    y = sqrt. 625

    y = 25

    a^2-c^2=b^2

    sqrt 400-625 = c

    20-25=c

    The correct answer is c=-5

    (-5,0)

    (5,0)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers