Find the most general antiderivative of the function.

g (t) = (5 + t + t^2) / square root of t

Question

Jude Keller

Mathematics

3 June, 05:45

Find the most general antiderivative of the function.

g (t) = (5 + t + t^2) / square root of t

+1

Answers (1)

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Esteban Le · Answer 1

G (t) = (5 + t + t^2) / √t = 5/√t + √t + t√t

∫g (t) dt = ∫ (5√t + √t + t√t) dt = 5 (t) ^3/2 / 3/2 + t^3/2 / 3/2 + t^5/2 / 5/2 + c = 10/3 t√t + 2/3 t√t + 2/5 t^2√t + c

Find the most general antiderivative of the function.g (t) = (5 + t + t^2) / square root of t

Find the most general antiderivative of the function.

g (t) = (5 + t + t^2) / square root of t