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7 April, 02:42

Use Newton's method to approximate a root of the equation / cos (x^2 + 3) = x^3 as follows. Let x_1 = 1 be the initial approximation. The second approximation x_2 is?

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  1. 7 April, 03:05
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    X_2 = x_1 - f (x_1) / f ' (x_1) = > x_2 = 1 + (cos4 - 1) / (2sin4 + 3) ≈ 1 - 7.64 ≈ - 6.64;
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