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28 September, 12:46

The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = - 2. What is the value of "a"? - 2 - 1 - 1/2

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  1. 28 September, 13:04
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    a = - 1.

    Step-by-step explanation:

    y = ax^2 - 4x + 3

    Convert to vertex form:-

    = a (x^2 - 4/a) + 3

    = a [ (x - 2/a) ^2 - 4/a^2 ] + 3

    From this we see that the line of symmetry is y = 2/a so

    2/a = - 2

    -2a = 2

    a = - 1.
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