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8 December, 16:30

If f (x) = 2 (x) ^2+5√ (x+2) what is the domian

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  1. 8 December, 16:44
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    Note that there is no real square root of a negative number so (x + 2) must be greater or equal to 0.

    When x + 2 = zero x = - 2

    So the domain is x> = - 2 or in interval notation:

    [-2, ∞)
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