Ask Question
21 June, 18:15

The masses of four planets in a solar system outside the Milky Way are given below.

Planet A: 5.97*10^24

Planet B: 3.30*10^23

Planet C: 1.89*10^27

Planet D: 4.87*10^24

What is the order of these planets from least to greatest?

+2
Answers (1)
  1. 21 June, 18:41
    0
    The answer is B, D, A, C.

    Let's all of them have the same exponent so we can compare them. Let 23 be the common exponent since it is the smallest one:

    Planet A: 5.97 * 10²⁴ = 5.97 * 10¹⁺²³ = 5.97 * 10 * 10²³ = 59.7 * 10²³

    Planet B: 3.30 * 10 ²³

    Planet C: 1.89 * 10 ²⁷ = 1.89 * 10⁴⁺²³ = 1.89 * 10⁴ * 10²³ = 1.89 * 10,000 * 10²³ = 18,900 * 10²³

    Planet D: 4.87*10 ²⁴ = 4.87 * 10¹⁺²³ = 4.87 * 10 * 10²³ = 48.7 * 10²³

    Since 3.30 * 10²³ < 48.7 * 10²³ < 59.7 * 10²³ < 18,900 * 10²³, then the order of these planets from least to greatest is B < D < A < C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The masses of four planets in a solar system outside the Milky Way are given below. Planet A: 5.97*10^24 Planet B: 3.30*10^23 Planet C: ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers