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21 October, 13:47

If csc Θ = 3/2 and the angle is in quadrant II, what is sec Θ?

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  1. 21 October, 14:14
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    sinθ = 1/cscθ = 2/3

    cos²θ = 1 - sin²θ = 1-4/9 = 5/9

    cosθ = - √5/3

    secθ = 1/cosθ = - 3/√5 = - 3√5/5
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