The vertex form of the equation of a parabola is y = 4 (x - 2) 2 - 1. What is the standard form of the equation?

A. y = 4x2 - 16x + 2

B. y = 4x2 - 16x + 15

C. y = 4x2 - 3

D. y = 16x2 - 5?

Y = 4 (x - 2) ² - 1

y = 4 (x² - 4x + 4) - 1

y = 4x² - 16x + 16 - 1

y = 4x² - 16x + 15

y = B (y)

Ok so your original equation was y=4 (x-2) ²-1

Therefore we need to expand the bracket to find the original equation.

To do this we need to find (x-2) ²=x²-4x+4

Now we multiply this by 4 and subtract 1

4x²-16x+15 Therefore B is the answer