Suppose the heights of men are normally distributed with mean, μ = 69.5 inches, and standard deviation, σ = 4 inches. suppose admission to a summer basketball camp requires that a camp participant must be in the top 40 % of men's heights, what is the minimum height that a camp participant can have in order to meet the camp's height admission requirement?

Question

Pansy

Mathematics

13 August, 22:26

Suppose the heights of men are normally distributed with mean, μ = 69.5 inches, and standard deviation, σ = 4 inches. suppose admission to a summer basketball camp requires that a camp participant must be in the top 40 % of men's heights, what is the minimum height that a camp participant can have in order to meet the camp's height admission requirement?

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Annie Nunez · Answer 1

To evaluate for the height we use the z-score formula given by:

z = (x-mu) / sig

where:

mean=mu=69.5 inches

sig=standard deviation=4

Given that:

P (x>X) = 0.40

then

P (x
thus the z-value corresponding to this is:

P (z
hence:

0.25 = (x-69.5) / 4

solving for x we get:

1=x-69.5

x=1+69.5

x=70.5

thus the minimum height should be 70.5 inches