one container is filled with a mixture that is 30% acid a second container is filled with the mixture that is 50% acid the second container is 50% larger than the first and the two containers are emptied into a third container what percent of acid is in the third container

42%

Step-by-step explanation:

x is for the volume of the container

the amount filled in the first container=0.30x

the volume of the first container + 50% of the second = (x+x*50%) = 1.5 x

the amount of acid in the second container = 1.5x * 50%=0.75x

total amount of acid in the third one = 0.3x+0.75x=1.05x

total solution : x+1.5x=2.5x

percentage=1.05x/2.5x = 0.42 or 42%