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Javion Strong
Mathematics
Yesterday, 22:44
How to solve vatiable equations 5x-7=7x-17
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Francesca Shea
Yesterday, 22:52
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Let's get the same terms on the same side.
I am going to remove 5x from both sides of the equation by subtracting 5x
5x - 5x - 7 = 7x - 5x - 17
-7 = 2x - 17 now lets remove the 17 from both sides
-7 + 17 = 2x (why do we add 17? Think of 2x - 17 as 2x + - 17. Tor remove a negative number we add it.
Now we finally have 10=2x and if we divide both sides by 2
10 = 2x
2 2 we get that x = 5
Let's check by substituting 5 in the original equation:
5 (5) - 7 = 7 (5) - 17
25 - 7 = 35 - 17
18 = 18
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