How many ways can we put 7 adults and 3 kids in line (where order matters) so that no two kids are next to each other?

Question

Deanna Osborne

Mathematics

24 August, 20:37

How many ways can we put 7 adults and 3 kids in line (where order matters) so that no two kids are next to each other?

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Answers (1)

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Carrot · Answer 1

Given that the order matters in this question, we shall apply the concept of permutation rather than computation. Thus, the number of ways in which that we can put 7 adults and 3 kids in line will be:

7P3

=210

There are more than 210 ways we can do this.