Twice a number plus another number is 310. The difference between the two numbers is 55. What are the two numbers

Lets say the first number is x and the second y

twice the first number is 2x plus another number (y) = 310

the difference of the numbers (x-y) = 55

we have simultaneous equations here:

2x+y=310

x-y=55

to cancel the y's the signs are different so you add the equations to give

3x=365

divide it by 3 to get:

x=121 and 2/3

using the easier equation x-y=55 we know x=121 2/3

now we substitute to get 121 2/3 - y=55

take 121 2/3 from both sides to get:

-y = - 66 2/3

therefore y = 66 2/3

that means x=121.6 (recurring) and y = 66.6 (recurring)

T us assume the two numbers to be "x" and "y".

Then

2x + y = 310

And

x - y = 55

Let us take the second equation and find the value of x in relation to y.

x - y = 55

x = y + 55

Now let us put the value of x in the first equation, we get

2x + y = 310

2 (y + 55) + y = 310

2y + 110 + y = 310

3y = 310 - 110

3y = 200

y = 200/3

= 66 2/3

Now putting the value of y in the second equation, we get

x - y = 55

x - (200/3) = 55

3x - 200 = 55 * 3

3x = 165 + 200

x = 365/3

= 121 2/3

So the value of x is 121 2/3 and the value of y is 66 2/3