Assume that there are 3 different issues of Sports Illustrated magazine, 4 different issues of Time, and 2 different issues of Newsweek, including the December 1st issue, on a rack. You choose 4 of them at random

1) What is the probability that you choose 1 issue of Sports Illustrated and 3 issues of Time?

2) What is the probability that you choose at least 1 of the Time magazines?

You choose 4 newspapers from 3+4+2=9 newspapers on the rack in total, which means you need to find the number of possible combinations (choose r objects from set of n objects), where r=4, n=9.

The formula for calculating the number of possible combinations is:

n! / (r! * (n-r) !)

The total number of ways to choose 4 newspapers form 9 is C (9,4) = 9*8*7*6*5 / 4! = 15120/24=630

1. The probability that you choose 1 issue of Sports Illustrated and 3 issues of Time is:

(C (3,1) * C (4,3)) / C (9,4)

C (3,1) = 3!/1!*2!=3

C (4,3) = 4!/1!*1!=24

3*24/630=72/630=0.114

2. The probability that you choose at least 1 of the Time magazines is:

1 - the probability that you choose no Time magazine

1-C (4,0) * 3/9^0 * (1-3/9) ^4

1-*0.33^4=1-0.011

0.989