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13 June, 17:30

Solving each system by Eliminating

x-y-2z=4

-x+2y+z=1

-x+y-3z=11

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Answers (1)
  1. 13 June, 17:55
    0
    x = 0

    y = 2

    z = - 3

    Step-by-step explanation:

    x-y-2z=4 (1)

    -x+2y+z=1 (2)

    -x+y-3z=11 (3)

    (1) + (3) = x-y-2z + (-x) + y-3z = 4+11

    = - 5z = 15

    -> z = - 3

    (1) + (2) = x - y - 2z + (-x) + 2y + z = 4+1

    = y-z = 5

    = y - (-3) = 5

    -> y = 2

    (1) = x-y-2z = 4

    = x - 2 - 2 * (-3) = 4

    -> x = 0
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