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Aden Mercer
Mathematics
9 September, 16:33
Solve each of the following equations for x.
2^x - 1 = 0
+4
Answers (
1
)
Shirley Farley
9 September, 16:52
0
The solution to the equation is x = 0
Step-by-step explanation:
Hi there!
First, let's write the equation:
2ˣ - 1 = 0
To solve it for x, let's add 1 to both sides of the equation:
2ˣ = 1
Apply log to both sides of the equation
log (2ˣ) = log (1)
Apply logrithm property: log (2ˣ) = x log (2)
x log (2) = log (1)
x log (2) = 0
x = 0
The solution is x = 0
Let's check the solution:
2ˣ - 1 = 0
x = 0
2⁰ - 1 = 0
1 - 1 = 0
0 = 0
The solution is correct!
Have a nice day!
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