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23 February, 07:05

Use the Law of Sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places.

A = 119 degrees, a = 128, b = 106

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  1. 23 February, 07:33
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    (sin119) / 128=sinB/106

    sinB=106 (sin119) / 128

    B=arcsin (106 (sin119) / 128)

    B≈46.41°

    C≈ (180-119-46.41) = 14.59°

    (sin119) / 128 = (sin14.59) / c

    c=128 (sin14.59) / sin119

    c≈36.87

    So the sides a, b, c are 128, 106, 36.87 respectively and

    angles a, b, c are 119°, 46.41°, 14.69° respectively.
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