3 (1 + 2b) + 2 < 71

Question

Sonia Bradshaw

Mathematics

3 December, 17:33

3 (1 + 2b) + 2 < 71

+1

Answers (1)

Know the Answer?

Leandro Roman · Answer 1

b < 11

Step-by-step explanation:

Step 1: Distribute

3 (1 + 2b) + 2 < 71

(3 * 1) + (3 * 2b) + 2 < 71

3 + 6b + 2 < 71

Step 2: Combine like terms

3 + 6b + 2 < 71

5 + 6b < 71

Step 3: Subtract 5 from both sides

5 + 6b - 5 < 71 - 5

6b < 66

Step 4: Divide both sides by 6

6b / 6 < 66 / 6

b < 11

Answer: b < 11