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12 February, 12:19

Which method of solving the quadratic equation would be the easiest to find the soulution for 2x^2 - 4x-3=0

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  1. 12 February, 12:23
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    Solve for x over the real numbers:

    2 x^2 - 4 x - 3 = 0

    Divide both sides by 2:

    x^2 - 2 x - 3/2 = 0

    Add 3/2 to both sides:

    x^2 - 2 x = 3/2

    Add 1 to both sides:

    x^2 - 2 x + 1 = 5/2

    Write the left hand side as a square:

    (x - 1) ^2 = 5/2

    Take the square root of both sides:

    x - 1 = sqrt (5/2) or x - 1 = - sqrt (5/2)

    Add 1 to both sides:

    x = 1 + sqrt (5/2) or x - 1 = - sqrt (5/2)

    Add 1 to both sides:

    Answer: x = 1 + sqrt (5/2) or x = 1 - sqrt (5/2)
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