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27 July, 03:08

a square stained window is divided into four congurent traiangular sections by iron edging to represent seasons of the year. Each diagonal measures 9 inches. What is the total length of iron edging needed to create the sqaure frame and two diagnols?

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  1. 27 July, 03:32
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    Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)

    Step-by-step explanation:

    Given:

    Length of diagonal = 9 in

    Find:

    Total length of iron needed to make the square frame and two diagonals.

    Computation:

    Area of square = 1/2 (diagonal) ²

    Area of square = 1/2 (9) ²

    Area of square = 40.5 in²

    Area of square = Side * Side

    40.5 in² = Side * Side

    Side = 6.36 (approx)

    Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 * diagonal)

    ⇒ (4 * 6.36) + (2 * 9)

    ⇒ (25.44) + (18)

    ⇒ 43.44 in

    Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
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