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20 February, 23:04

One Solution, infinitely many, or no solutions?

x-3y=27,2x=6y-14

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  1. 20 February, 23:30
    0
    Ok, let's take it step by step.

    Take the first equation and solve for x.

    x-3y=27

    x=3y+27

    Substitute x into the second equation.

    2 (3y+27) = 6y-14

    6y+68=6y-14

    68=-14

    Since 68 does not = - 14, the system of equations has no solution.
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