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Zaid Sheppard
Mathematics
18 February, 09:20
What are the solutions to 4 (x+5) ^2=4?
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Copper
18 February, 09:31
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(X+5) ²=4/4
X+5=1, X+5=-1
X=1-5 X=-1-5
X=-4 X=-6
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Tyson
18 February, 09:45
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First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4 (x + 4) (x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = - 4 and x = - 6.
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