Ask Question
30 August, 01:44

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104. So I have to find r. But is this right: 7104 = 444r^4 r^4 = 16 r = 2 Or should it be r^3? I'm never sure if the power is = the number of terms missing or something completely unrelated.

+1
Answers (1)
  1. 30 August, 02:11
    0
    Third term = t3 = ar^2 = 444 eq. (1)

    Seventh term = t7 = ar^6 = 7104 eq. (2)

    By solving (1) and (2) we get,

    ar^2 = 444

    => a = 444 / r^2 eq. (3)

    And ar^6 = 7104

    (444/r^2) r^6 = 7104

    444 r^4 = 7104

    r^4 = 7104/444

    = 16

    r2 = 4

    r = 2

    Substitute r value in (3)

    a = 444 / r^2

    = 444 / 2^2

    = 444 / 4

    = 111

    Therefore a = 111 and r = 2

    Therefore t6 = ar^5

    = 111 (2) ^5

    = 111 (32)

    = 3552.

    Therefore the 6th term in the geometric series is 3552.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104. So I have to find r. But is this right: 7104 = 444r^4 r^4 = 16 r = 2 Or ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers