Use substitution process to find x, y, and z from the equations 2x+4y+3z=14, y+3z=11, z=4

Work backwards.

Start with z = 4.

Now deal with the middle equation

y + 3z = 11 Substitute z = 4 and solve for y

y + 3 (4) = 11 Subtract 12 from both sides

y + 12 = 11

y + 12 - 12 = 11 - 12 Combine terms on the left and right

y = - 1 Now use the top equation for x

z = 4 z still = 4

2x + 4 (-1) + 3 (4) = 14

2x - 4 + 12 = 14 Solve 3z

2x + 8 = 14 Subtract 8

2x + 8 - 8 = 14 - 8 Combine

2x = 6 Divide by 2

x = 6/2

x = 3

Answer

x = 3

y = - 1

z = 4