A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week. Of the 250 employed individuals surveyed, 42 responded that they did work at home at least once per week. Construct a 99% confidence interval for the population proportion of employed individuals who work at home at least once per week.

The lower bound is nothing.

(Round to three decimal places as needed.)

Question

Kareem Browning

Mathematics

5 September, 20:53

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week. Of the 250 employed individuals surveyed, 42 responded that they did work at home at least once per week. Construct a 99% confidence interval for the population proportion of employed individuals who work at home at least once per week.

The lower bound is nothing.

(Round to three decimal places as needed.)

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Answers (1)

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General · Answer 1

solution is given below

Step-by-step explanation:

A simple random sample size n = 250. Of the 250 employed individuals surveyed, 42 responded that they did work at home at least once per week.

Construct 99% confidence interval for population

For proportion : 42 / 250 = 1/10 = 0.16

Mean = 2.5 * sqrt [ 0.1 * 0.9 / 250]

= 2.5 * 0.01

= 0.47

Construction of hypothesis:

0.10 - 0.047 < p < 0.10 + 0.047