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4 June, 09:05

I am the fewest number of armadillos that meet the following conditions when grouped by twos by threes or by fours there is one left over when grouped by five there is none left over

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  1. 4 June, 09:13
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    25.

    25/5 = 5

    25/4 = 6 and one left over

    25/3 = 8 and one left over
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