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Kameron Conner
Mathematics
3 June, 03:24
Answer in factored form x^2+11x+7
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Nicolas Huynh
3 June, 03:29
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X² + 11x + 7
because 7 is a prime number, this doesn't factor prettily. you'll want to use the quadratic formula; if you aren't familiar with it, i'd either research it or look it up in your textbook, because it's clunky and not easily understood in this format:
(-b ± √ ((b) ² - 4ac)) / (2a)
in your equation x² + 11x + 7 ... a = 1, b = 11, and c = 7. what you do is you take the coefficients of every term, then plug it into your equation:
(-11 ± √ ((11) ² - 4 (1) (7)) / (2 (1))
not pretty, i know. but, regardless, you can simplify it:
(-11 ± √ ((11) ² - 4 (1) (7)) / (2 (1))
(-11 ± √ (121 - 28)) / 2
(-11 ± √93) / 2
and you can't simplify it further. - 11 isn't divisible by 2, and 93 doesn't have a perfect square that you can take out from beneath the radical. the ± plus/minus symbol indicates that you have 2 answers, so you can write them out separately:
(x - (-11 - √93) / 2) and (x + (-11 - √93) / 2)
they look confusing, but those are your two factors. they can be simplified just slightly by changing the signs in the middle due to the - 11:
(x + (11 + √93) / 2) (x - (11 - √93) / 2)
and how these would read, just in case the formatting is too confusing for you: x plus the fraction 11 + root 93 divided by 2. the 11s and root 93s are your numerator, 2s are your denominator.
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