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5 February, 20:52

Find three consecutive integers such that the sum of the first, twice the second, and three times the third is - 76

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  1. 5 February, 21:13
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    -14, - 13, - 12.

    This is done by calling the first number x, the second x+1 and the third x+2. Then write the equation using the descriptions as ...

    x + 2 (x+1) + 3 (x+2) = - 76

    Distribute and solve.
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