Use the fundamental theorem of algebra to determine the number of roots for each polynomial function shown.

1.) f (x) = 2x3 + x2 - 7x + 1 has _ roots.

2.) f (x) = - 3x + 5x2 + 8 has _ roots.

3.) f (x) = (x2 + 6) 2 has ___ roots.

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Mathematics

29 April, 17:56

Use the fundamental theorem of algebra to determine the number of roots for each polynomial function shown.

1.) f (x) = 2x3 + x2 - 7x + 1 has _ roots.

2.) f (x) = - 3x + 5x2 + 8 has _ roots.

3.) f (x) = (x2 + 6) 2 has ___ roots.

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Tatum Mercado · Answer 1

The fundamental theorem of algebra says that a polynomial has the same number of roots as its highest degree. #1 is a 3rd degree polynomial so it has 3 roots. #2 is a second degree polynomial so it has 2 roots. #3 is also a second degree. Roots are the same thing as solutions and zeros of the polynomials. The places on the graph where the curve goes through the x-axis. I love polynomials; they're my favorite.

Morgan Roach · Answer 2

1.) f (x) = 2x3 + x2 - 7x + 1 has 3 roots.

2.) f (x) = - 3x + 5x2 + 8 has 2 roots.

3.) f (x) = (x2 + 6) 2 has 4 roots.

Use the fundamental theorem of algebra to determine the number of roots for each polynomial function shown.1.) f (x) = 2x3 + x2 - 7x + 1 has ___ roots.2.) f (x) = - 3x + 5x2 + 8 has ___ roots.3.) f (x) = (x2 + 6) 2 has ___ roots.

Use the fundamental theorem of algebra to determine the number of roots for each polynomial function shown.

1.) f (x) = 2x3 + x2 - 7x + 1 has _ roots.

2.) f (x) = - 3x + 5x2 + 8 has _ roots.

3.) f (x) = (x2 + 6) 2 has ___ roots.