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13 December, 15:22

Differentiate: y=1+cosx/1-cosx ... ?

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  1. 13 December, 15:38
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    The answer for the given question above would be calculated as:

    y = (1 + cos (x)) / (1 - cos (x))

    Using the quotient rule.

    dy/dx = [ (-sin (x)) (1 - cos (x)) - (1 + cos (x)) (sin (x)) ] / [ (1 - cos (x)) ^2 ]

    dy/dx = [ - sin (x) + sin (x) cos (x) - sin (x) - sin (x) cos (x) ] / [ 1 - cos (x) ]^2

    dy/dx = [ - 2sin (x) ] / [ 1 - cos (x) ]^2

    The answer is dy/dx = [ - 2sin (x) ] / [ 1 - cos (x) ]^2
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