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19 June, 06:29

A. Set up an equation to represent the distance the cheetah covered in terms of t minutes running at maximum speed. Remember, units of distance and time must agree. Use the conversion information from the warm-up to write a rate in miles per minute.

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  1. 19 June, 06:51
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    The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.

    Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t

    There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.

    Part B:

    Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.

    Part C:

    If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by

    d = 1.167 x 8 = 9.33 miles.

    Part D:

    If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by

    d = 40/60 x 8 = 5.33 miles

    Part E:

    The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by

    9.33 miles - 5.33 miles = 4 miles.

    Part F:

    The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by

    9.33 : 5.33 = 1.75 : 1.

    Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.
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