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28 October, 21:18

Solve for x

2x^2/3=dg

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Answers (1)
  1. 28 October, 21:38
    0
    (2x²/3) = dg

    2x²=3dg

    x² = ((3dg) / 2)

    So x=√ ((3dg) / 2) or x=-√ ((3dg) / 2)
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