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Danika Gibbs
Mathematics
28 October, 21:18
Solve for x
2x^2/3=dg
+3
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1
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Amaya Valentine
28 October, 21:38
0
(2x²/3) = dg
2x²=3dg
x² = ((3dg) / 2)
So x=√ ((3dg) / 2) or x=-√ ((3dg) / 2)
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