The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

11, 20,29, ...

Find the 30th term.

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1 + (n-1) d

an = nth term

a1 = first term

n = nth position

d = common difference

We are looking for the 30th term, so our n=30

d = a2-a1

d = 20-11

d = 9

Using the formula

an = a1 + (n-1) d

a30 = 11 + (30-1) 9

a30 = 11 + (29) 9

a30 = 11 + (29*9)

a30 = 11+261

a30 = 272

Therefore, the 30th term is 272