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13 March, 03:20

Find the center and the radius of the circle with the equation x^2+2x+y^2-2y-14=0

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  1. 13 March, 03:50
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    The standard form of a circle is (x-h) ² + (y-k) ²=r², (h, k) is the center of the circle, r is the radius.

    x²+2x+y²-2y-14=0

    make squares by adding (half of b) squared: the "b" for x is 2, the "b" for y is "-2" in this case, so add 1 to each, then subtract 1:

    x²+2x+1+y²-2y+1-1-1-14=0

    (x+1) ² + (y-1) ²=4²

    so the center is at (-1,1) and the radius is 4.
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