Suppose you're playing hide and seek in a big house with 4 rooms upstairs and 5 rooms downstairs. You've looked in 2 of the downstairs rooms and know the hider is not those rooms. What is the probability the hider is downstairs given this information? (Assume equally likely outcomes).

Question

Jacoby Gill

Mathematics

23 April, 18:26

Suppose you're playing hide and seek in a big house with 4 rooms upstairs and 5 rooms downstairs. You've looked in 2 of the downstairs rooms and know the hider is not those rooms. What is the probability the hider is downstairs given this information? (Assume equally likely outcomes).

+1

Answers (1)

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Sebastian Daugherty · Answer 1

3/7

Step-by-step explanation:

1. there were a total of 9 rooms but you minus two due to the fact the hider isnt there and so you are left with 7

2. You also minus two from five and that gives you three

3. they ask for only downstairs so it would be 3/7