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14 October, 20:46

Use doubles minus one to solve 8'+7

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  1. 14 October, 21:12
    0
    Well we have

    8 + 7. The method used would be like thos

    8 + 7

    ~2 (-1) + 10 + 7

    ~-2 + 10 + 7

    ~8 + 7

    Double minus one is this here > (-1) + (-1) = - 1 - 1 = - 2 = 2 (-1)
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