Ask Question
27 November, 13:52

Given: ΔАВС, m∠ACB = 90° CD ⊥ AB, m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC

+4
Answers (1)
  1. 27 November, 14:11
    0
    Area=1/2*base*height

    given that ABC is right angled triangle, the height will be given by:

    tan theta=opposite/adjacent

    tan 60=h/6

    h=6tan60

    =10.4

    thus the area will be:

    A=1/2x6x10.4

    =31.2 cm^2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Given: ΔАВС, m∠ACB = 90° CD ⊥ AB, m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers