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16 February, 00:53

Lisa drove 120 miles, then increased her speed by 30 miles per hour for 270 miles. If the second part of the drive took 1 hour longer than the first part, find her average speed

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  1. 16 February, 01:13
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    Let the speed = r

    120/r = the time it took to go the first 120 hours.

    270 / (r + 30) = the time it took to go the second part of the trip.

    270 / (r + 30) - 120/r = 1

    Multiply through by r * (r + 30)

    270 * r - 120 * (r + 30) = 1 * r * (r + 30) Remove the brackets.

    270r - 120r - 3600 = r^2 + 30r Collect left like terms.

    150r - 3600 = r^2 + 30r Transfer the left side to the right.

    0 = r^2 - 120r + 3600 This should factor

    (r - 60) (r - 60) = 0

    r = 60 and r1 = 60

    270 / (30 + 60) = 270 / 90 = 3 hours

    120 / 60 = 2 hours. So far so good.

    Now we need to get the average speed.

    d = 270 + 120

    d = 390

    t = 3 + 2

    t = 5 hours.

    Average speed = d / t

    Average speed = 390 / 5

    Average speed = 78 miles / hour.
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