Wyatt room is a rectangular with a perimeter of 40 feet. the width of room is 8 feet. what is the length of the room

Question

Harold Morales

Mathematics

23 October, 06:37

Wyatt room is a rectangular with a perimeter of 40 feet. the width of room is 8 feet. what is the length of the room

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Answers (2)

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Reagan Wallace · Answer 1

Width = 8ft

lenght=x

Perimeter of a rectangle=2 length + 2 width

Therefore:

2x+2 (8 ft) = 40 ft

2x+16 ft=40 ft

2x=40 ft-16ft

2x=24 ft

x=24 ft/2

x=12 ft

Answer: the lenght of the room will be 12 ft.

Jayson Huffman · Answer 2

Perimiter=2 (legnth+width)

perimiter=40

width=8

40=2 (legnth+8)

divide both sides by 2

20=legnth+8

minus 8 both sides

12=legnth

legnth=12 feet