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10 January, 20:00

Crickets can jump with a vertical velocity of up to 14 ft/s. Which equation models the height of such a jump, in feet, after t seconds? h (t) = - 16t2 + v0t + h0

h (t) = - 16t2 + v0t + 14

h (t) = - 16t2 + 14t

h (t) = - 16t2 + 14t + 14

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Answers (2)
  1. 10 January, 20:13
    0
    Acceleration is simplified by assuming it is the constant - g

    a=-g we integrate this with respect to time to get v ...

    v=-gt+C where C is the initial velocity in this case 14ft/s so

    v=-gt+14 integrate again to get the height function

    h = (-gt^2) / 2 + 14t + C we are not given an initial height so C is 0

    h (t) = 14t-gt^2/2 letting g=32 and neatening up a bit ...

    h (t) = 14t-16t^2
  2. 10 January, 20:21
    0
    And time 0 h (t) = 0

    so which one must t be?
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