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15 October, 19:00

Starting at home, luis traveled uphill to the hardware store for 30 minutes st just 8mph. he then traveled back home along the same path downhill at a speed of 24 mph. what is his average speed for the entire trip from home to the hardware store and back?

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  1. 15 October, 19:09
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    1.

    The main formula we use is:

    Distance traveled = average Speed * Time,

    in short: D = S * T

    2.

    " luis traveled uphill to the hardware store for 30 minutes at speed 8mph. "

    we have the speed and the time = 30 min = 1/2 h

    so we can find distance:

    D=ST=8 (mi/h) * 1/2 (h) = 4 mi

    3.

    Now we have D, and the speed 24 mph, so we can find the time it takes Luis to travel back home:

    D=S*T

    T = D/S = 4 (mi) / 24 (mi/h) = 1/6 h

    4.

    The total distance is D+D = 4 + 4 = 8 (mi)

    the total time is 1/2 + 1/6 = 3/6 + 1/6 = 4/6 = 2/3 (h)

    So we can find the average speed of the entire trip is:

    S=8 / (2/3) = 8 * (3/2) = 4*3=12 (mph)

    Answer : 12 mph
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