A parabola has a vertex at (-1, 0) and opens down. What is the equation of the parabola?

y = - x^2 - 1

y = - (x - 1) ^2

y = - (x + 1) ^2

Question

Nathaly Cochran

Mathematics

14 September, 05:28

A parabola has a vertex at (-1, 0) and opens down. What is the equation of the parabola?

y = - x^2 - 1

y = - (x - 1) ^2

y = - (x + 1) ^2

+1

Answers (1)

Know the Answer?

Aaden Montgomery · Answer 1

Vertex form

for

y=a (x-h) ^2+k

vertex is (h, k)

and if a is poisitve it opens up and if it is negative it opens down

so it is opening down and has vertex at (-1,0)

y = - (x - (-1)) ^2+0

y = - (x+1) ^2

last option

A parabola has a vertex at (-1, 0) and opens down. What is the equation of the parabola?y = - x^2 - 1y = - (x - 1) ^2y = - (x + 1) ^2

A parabola has a vertex at (-1, 0) and opens down. What is the equation of the parabola?

y = - x^2 - 1

y = - (x - 1) ^2

y = - (x + 1) ^2