A cat adoption facility takes in an average of 4 cats per day. The facility has to keep their cat occupancy below 200. Currently, the facility has 172 cats.

If none of their cats get adopted, how many more days, x, can the facility continue to take in cats? Select the inequality that includes the largest number of days this facility can continue to take in cats without exceeding its occupancy limit.

A. x < 7

B. x < 28

C. x < 50

D. x < 24

A. x<7

Step-by-step explanation:

We know three things:

The facility takes 4 cats per day The facility has to keep the occupancy below 200 Currently, the facility has 172 cats

Now we want to know how many more days the facility can continue to take in cats if none of their cats get adopted.

First, we want to know how many cats until the facility exceeds the occupancy and to do it we have to subtract the occupancy minus the cats they already have:

200 - 172 = 28

With this answer, we know that if they get 28 more cats they will have 200 cats and the occupancy has to be below 200.

Now we want to know how many days will it take them to get 28 more cats:

We know that every day they get 4 cats, so we are going to divide the number of cats to get 200 by the number of cats they get every day:

28 (cats) / 4 (cats per day) = 7 days

So in 7 days, they will pass their occupancy, which means that they can only take cats less than 7 days.

The expression will be:

x < 7

Where:

x is how many more days they can take in cats

< means less than