How many pounds of hamburger worth $1.05 per pound must be mixed with 60 pounds of hamburger worth $0.90 per pound to produce hamburger worth $1.00 per pound? Which of the following systems represents the word problem if x = pounds of hamburger worth $1.05 per pound? x + y = 60 and 1.05x + 0.90 (60) = 1.00y x + 60 = y and 1.05x + 1.00y = 0.90 (60) x + 60 = y and 1.05x + 0.90 (60) = 1.00y

Question

Jaydin Sellers

Mathematics

2 June, 11:10

How many pounds of hamburger worth $1.05 per pound must be mixed with 60 pounds of hamburger worth $0.90 per pound to produce hamburger worth $1.00 per pound? Which of the following systems represents the word problem if x = pounds of hamburger worth $1.05 per pound? x + y = 60 and 1.05x + 0.90 (60) = 1.00y x + 60 = y and 1.05x + 1.00y = 0.90 (60) x + 60 = y and 1.05x + 0.90 (60) = 1.00y

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Answers (1)

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Nia Patrick · Answer 1

You are adding x pounds of hamburger to an existing 60 pounds. You want the total price to be 1.00 per pound times the total number of pounds.

The appropriate choice is the last one:

x + 60 = y and 1.05x + 0.90 (60) = 1.00y