Ask Question
6 August, 01:37

The lenght of a rectangle is 4 meters more than twice the width. Find the greatest possible value for the width if the perimeter is at most 38 meters.

+3
Answers (1)
  1. 6 August, 01:46
    0
    2 (L + W) < = P

    L = 2W + 4

    P 38

    2 (2W+4 + W) = 38

    4W + 8 + 2W = 38

    6W + 8 = 38

    6W = 38 - 8

    6W = 30

    W = 30/6 = 5 ... the greatest possible value is 5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The lenght of a rectangle is 4 meters more than twice the width. Find the greatest possible value for the width if the perimeter is at most ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers