The circuit above has a current of 0.32 A coming out of the power supply. Resistors R1, R2, and R3 have resistances of 408 LaTeX: / OmegaΩ, 2,296 LaTeX: / OmegaΩ, and 3,309 LaTeX: / OmegaΩ respectively, what is the voltage of the power supply

1924 volts

Step-by-step explanation:

From Ohm's Law:

Voltage (V) = Current (I) x Resistance (R)

V = I R ... (1)

I = 0.32 A

R₁ = 408 Ω

R₂ = 2,296Ω

R₃ = 3,309Ω

Total Resistance = 408 + 2296+3309

= 6,013‬Ω

Substituting into (1), we have:

V = 0.32 x 6,013‬

= 1,924.16‬ volts

≅ 1924 volts