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27 December, 18:57

Question 3 Unsaved Factor as the sum of cubes: 27x12+8y3 Question 3 options: (3x6+2y) (9x16-6x4y+4y2)

(x4+2y) (x8-6x4y+4y2)

(3x4+2y) (9x8-6x4y+4y2)

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Answers (2)
  1. 27 December, 19:01
    0
    The correct answer is the third one (3x4+2y) (9x8-6x4y+4y2).
  2. 27 December, 19:20
    0
    (3x4+2y) (9x8-6x4y+4y2)
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