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26 January, 02:19

There are three consecutive even numbers such that twice the first is 20 more than the second. Find the number

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  1. 26 January, 02:40
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    22, 24, 26

    Step-by-step explanation:

    2n is an even number.

    Your three even numbers are 2n, 2n + 2, 2n + 4

    Twice the first is 20 more than the second.

    2n * 2 = 2n + 2 + 20

    Simplify:

    4n = 2n + 22

    Use simultaneous equations to solve n.

    4n = 2n + 22 - 2n

    2n = 22 : 2

    n = 11

    Subsitiye n into the three even numbers.

    2n, 2n + 2, 2n + 4

    2 * 11, 2 * 11 + 2, 2 * 11 + 4

    22, 24, 26

    Check that the numbers meet the requirements.

    22 * 2 = 24 + 20

    44 = 44
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